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What weight of ferrous ammonium sulphate is needed to prepare 100 ml of 0.1 normal solution (mol. wt. 392)A. 39.2 gmB. 3.92 gmC. 1.96 gmD. 19.6 gm

Answer» Correct Answer - B
`w=(0.1xx100xx392)/(1000)=3.92 g`


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