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What weight of `HNO_(3)` is needed to convert `5g` of iodine into iodic acid according to the reaction, `I_(2)+HNO_(3)rarrHIO_(3)+NO_(2)+H_(2)O`A. `12.4 g`B. `24.8 g`C. `0.248 g`D. `49.6 g` |
Answer» Correct Answer - A `{:(1e,+,N^(5+),rarr,N^(4+),),(,,I_(2)^(0),rarr,2I^(5+),+10e),(,,,,,):}` Meq. Of `HNO_(3)=` Meg. Of `I_(2)` `(w)/(63//1)xx1000xx=(5)/(254//10)xx1000` `w=12.4g` |
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