What weight of NaOH will contain the same number of oxygen atoms as are present in 9.8 g of sulphuric acid ? (Na = 23, O = 16, S = 32, H = 1)

What weight of NaOH will contain the same number of oxygen atoms as ar

1.	What weight of NaOH will contain the same number of oxygen atoms as are present in 9.8 g of sulphuric acid ? (Na = 23, O = 16, S = 32, H = 1)
Answer» 4 g 16 g 40 g 160 g Solution :9.8 g of sulphuric acid `(H_2SO_4)` contains `4xx6.02xx10^(22) = 2.408 xx10^(23)` ATOMS of oxygen Mass of NaOH containing same number of oxygen ATOM `("No. of oxygen atoms in " H_2SO_4xx "Mol. mass of NaOH" )/("Avogadro Number")` `=(4xx6.02xx10^(22)xx40)/(6.02xx10^(23)) =16 g`