1.

What weight of slaked lime will be required to decompose completely 4 grams ammonium chloride

Answer»

`2.77g`
`3.5g`
`5.5g`
`5.44g`

SOLUTION :`UNDERSET(2xx53.5g)(2NH_(4)Cl)+underset(74g)(Ca(OH)_(2))rarrCaCl_(2)+2NH_(3)+2H_(2)O`


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