What weight of zinc would be required to produce enough hydrogen to reduce completely 7.95 g of CuO.

What weight of zinc would be required to produce enough hydrogen to re

1.	What weight of zinc would be required to produce enough hydrogen to reduce completely 7.95 g of CuO.
Answer» Solution :The corresponding equations are : `underset(65.38 g)(Zn) + H_(2)SO_(4) to underset(2.016 g)(ZnSO_(4)) + H_(2)` and `underset(79.55 g)(CuO) + H_(2) to underset(2.016 g)(Cu) + H_(2)O` `therefore 79.55 g` of CuO REQUIRE for REDUCTION, hydrogen = 2.016 g. `therefore 7.95 g` of CuO will require for reduction, hydrogen `=(2.016)/(79.55) xx 7.95 = 0.201 g` Moreover, `therefore 2.016 g` of `H_(2)` is produced by ZINC = 65.38 g `therefore 0.201` g of `H_(2)` will be produced by zinc `=(65.38)/(2.016) xx 0.201 = 6.52 g` Hence, the amount of zinc required to REDUCE 5 g of CuO is 6.52 g