What weight of zinc would be required to produce enough hydrogen by reacting with dilute HCl to reduce completely 8.5 g of copper oxide to copper ?

What weight of zinc would be required to produce enough hydrogen by re

1.	What weight of zinc would be required to produce enough hydrogen by reacting with dilute HCl to reduce completely 8.5 g of copper oxide to copper ?
Answer» Solution :Zinc will react with an acid (say dilute HCl) to evolve hydrogen gas which will reduce copper OXIDE to copper `Zn+2HClrarrZnCl_(2)+H_(2)` `CuO+H_(2)rarrCu+H_(2)O` `underset(65g)(Zn)+underset(63.5+16)(2HCl)+underset((=79.5g))(CuO)rarrZnCl_(2)+Cu+H_(2)O` 79.5 G of CuO require Zn = 65 g 8.5 g of CuO require `Zn=(65)/(79.5)xx8.5=6.95g`.