1.

What wil be the products of electrolysis of an aqueous solution of AgNO_(3) with silver electrodes ?

Answer»

AG from Ag anode dissolves while `Ag^(+)` from solution gets deposited on cathode.
Ag is liberated at cathode and `O_(2)` isliberated at anode.
Ag at cathode and nitric acid at anode is liberated.
No reaction takes place.

Solution :`AgNO_(3)RARR Ag^(+)+NO_(3)^(-)` (AQUEOUS solution)
At cathode : `Ag_((aq))^(+)+e^(-)rarr Ag, E^(@)=+0.80 V`
`2H_(2)O_((l))+2e rarr H_(2)+2OH^(-), E^(@)=-0.83 V`
Since reduction potential of `Ag^(+)` is higher than `H_(2)O`, `Ag^(+)` are REDUCED to Ag.
At anode :
`Ag rarr Ag_((aq))^(+) + e^(-), E^(@)=-0.80 V`
`2H_(2)O rarr O_(2)+4H^(-)+4e^(-), E^(@)= - 1.23 V`
Since oxidation potential of Ag is higher than `H_(2)O`, Ag of SILVER anode is oxidised. Theoxidation potential of `NO_(3)^(-)` is lower than `H_(2)O`.


Discussion

No Comment Found