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What wil be the products of electrolysis of an aqueous solution of AgNO_(3) with silver electrodes ? |
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Answer» AG from Ag anode dissolves while `Ag^(+)` from solution gets deposited on cathode. At cathode : `Ag_((aq))^(+)+e^(-)rarr Ag, E^(@)=+0.80 V` `2H_(2)O_((l))+2e rarr H_(2)+2OH^(-), E^(@)=-0.83 V` Since reduction potential of `Ag^(+)` is higher than `H_(2)O`, `Ag^(+)` are REDUCED to Ag. At anode : `Ag rarr Ag_((aq))^(+) + e^(-), E^(@)=-0.80 V` `2H_(2)O rarr O_(2)+4H^(-)+4e^(-), E^(@)= - 1.23 V` Since oxidation potential of Ag is higher than `H_(2)O`, Ag of SILVER anode is oxidised. Theoxidation potential of `NO_(3)^(-)` is lower than `H_(2)O`. |
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