1.

What will be de-Broglie wavelength of an electron moving with a velocity of 1.2xx10^5 "ms"^(-1)

Answer»

`6.071xx10^(-9)`
`3.133xx10^(-37)`
`6.626xx10^(-9)`
`6.018xx10^(-7)`

SOLUTION :`lambda=h/p , p=mv`
`lambda=h/"mv"=(6.62xx10^(-34))/(9.1xx10^(-31)xx1.2xx10^5)`
`lambda=6.071xx10^(-9)`m


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