What will be DeltaH for the reaction, CH_(2)Cl_(2)rarrC+2H+2Cl? (B.E. of C-H and C-Cl bonds are "416 kJ mol"^(-1) and "325 kJ mol"^(-1) respectively)

What will be DeltaH for the reaction, CH_(2)Cl_(2)rarrC+2H+2Cl? (B.E

1.	What will be DeltaH for the reaction, CH_(2)Cl_(2)rarrC+2H+2Cl? (B.E. of C-H and C-Cl bonds are "416 kJ mol"^(-1) and "325 kJ mol"^(-1) respectively)
Answer» 832 KJ 1482 kJ 650 kJ 1855 kJ Solution :`H-OVERSET(H)overset(\|)UNDERSET(Cl)underset(\|)C-ClrarrC=2H+2Cl` `DeltaH=SigmaB.E._(R)-SigmaB.E._(P)` `=2xxB.E.(C-H)+2xxB.E.(C-Cl)` `=2xx416+2xx325="1482 kJ"`