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| 1. |
What will be effect on maximum height of a projectile when its angle of projection is changed |
| Answer» maximum height =\xa0{tex} \\frac{ u^{2} sin^{2} \\alpha }{2g}{/tex}for α=30,maximum height =\xa0{tex} \\frac{ u^{2} sin^{2}30}{2g} = \\frac{ u^{2} }{8g}{/tex}for α=60,maximum height =\xa0{tex} \\frac{ u^{2} sin^{2}60}{2g} = \\frac{3 u^{2} }{8g}{/tex}So maximum height will increase\xa0 | |