1.

What will be normality of the solution obtained by adding 200 mL of pure water to 100 mL of 0.2 N HCl solution ?

Answer»


Solution :APPLYING normality equation :
`OVERSET(("conc."))(N_(1)V_(1))-=overset(("dilute"))(N_(2)V_(2))`
`0.2xx100=N_(2)xx300orN_(2)=(0.2xx100)/(300)=0.067N`.


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