What will be normality of the solution of the mixture of 40 mL, 0.2 M H_(2)SO_(4(aq)) and 60 mL 0.3 M H_(2)SO_(4(aq)) ?

What will be normality of the solution of the mixture of 40 mL, 0.2 M

1.	What will be normality of the solution of the mixture of 40 mL, 0.2 M H_(2)SO_(4(aq)) and 60 mL 0.3 M H_(2)SO_(4(aq)) ?
Answer» 0.26 N 0.25 N 0.5 N 0.52 N Solution :`M_(3) = (M_(1)V_(1)+M_(2)V_(2))/(V_(3))` `= ((40xx0.2) + (60xx0.3))/(100)` `= (8.0+ 18.0)/(100)` `= 0.26M` Where : `{:(M_(1)=0.2M),(V_(1)=40ML):}}H_(2)SO_(4)` `{:(M_(2)=0.3M),(V_(2)=60mL):}}H_(2)SO_(4)` `v_(3)=(60+40)mL` `= 100 mL` `M_(3)=` Morality of mix solution ` 0.26=` Molarity of mixed `H_(2)SO_(4)` solution MOLECULAR mass of `H_(2)SO_(4) = 2(H) + S + 4 (O)` `= 2(1) + 32+4(16)` `= 98g*MOL^(-1)` BASICITY of `H_(2)SO_(4) = 2= ` no. of `H^(+)` `:.` Equivalent wt. of `H_(2)SO_(4)= 98//2=49` Normality `=("Molarity" xx "Molecular weight")/("Equivalentweight")` `= 0.26xx98)/(49) = 0.52 N H_(2)SO_(4)`