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What will be percentage decrease in weight of body when taken to the depth of 64 km below the surface of earth ? |
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Answer» SOLUTION :`g. = g(1-(d)/(R ))` `g. - g = (-GD)/(R )` `g - g. = (gd)/(R )` PERCENTAGE DECREASE in weight `= ((mg - mg.)/(mg))XX 100` `= ((g-g.)/(g)) xx 100` `= (gd)/(Rg) xx 100` `= (d)/(R ) xx 100` `= (64)/(6,400) xx 100` = 1% |
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