1.

What will be percentage decrease in weight of body when taken to the depth of 64 km below the surface of earth ?

Answer»

SOLUTION :`g. = g(1-(d)/(R ))`
`g. - g = (-GD)/(R )`
`g - g. = (gd)/(R )`
PERCENTAGE DECREASE in weight `= ((mg - mg.)/(mg))XX 100`
`= ((g-g.)/(g)) xx 100`
`= (gd)/(Rg) xx 100`
`= (d)/(R ) xx 100`
`= (64)/(6,400) xx 100`
= 1%


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