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What will be the angle of diffracting for the first minimum due to Fraunhofer diffraction with sources of light of wavelength `550nm` and slit of width `0.55mm`?A. 0.001 radB. 0.01 radC. 1 radD. 0.1 rad |
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Answer» Correct Answer - A Using `d sin theta = n lamda`, for `n =1` `sin theta = (lamda)/(d) =(550 xx10^(-9))/(0.55 xx10^(-3))=10^(-3)=0.001 rad`. |
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