1.

What will be the concentration of iodine in solution?A. `1.1M`B. `0.011M`C. `0.0011M`D. `0.11M`

Answer» Correct Answer - C
Molarity `(M)=(n_(I_2))/(V_L)`
`n_(I_2)=(Mass_(I_2))/(Molar mass_(I_2))=(0.070g)/(254g mol^(-1))`
`V_L=250 mLxx(IL)/(1000mL)`
`:. M=(0.070g)/(254 g mol^(-1)xx250mL)xx((1000mL)/(1L))`
`=0.0011 mol L^(-1)`


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