1.

What will be the correct order for the wavelengths of absorption in the visible region for the following : [Ni(NO2)6]4-, [Ni(NH3)6]2+, [Ni(H2O)6]2+

Answer»

The order of the ligand in the spectrochemical series is H2O < NH3 < NO2-

Hence the wavelength of the light observed will be in the order :

[Ni(H2O)6]2+ < [Ni(NH3)6]2+ < [Ni(NO2)6]4-

Thus, the wavelength of light absorbed (E = \(\frac{hc}{\lambda}\) ) will be in the opposite order :

[Ni(H2O)6]2+ > [Ni(NH3)6]2+ > [Ni(NO2)6]4-



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