What will be the difference in temperatures between two sides of a metallic plate 10 mm thick if heat is conducted at the rate of 5 xx 10^5cal/min/m^2 . K for metal is 0.7 cal s^(-1)cm^(-1) ""^@C^(-1) .

What will be the difference in temperatures between two sides of a met

1.	What will be the difference in temperatures between two sides of a metallic plate 10 mm thick if heat is conducted at the rate of 5 xx 10^5cal/min/m^2 . K for metal is 0.7 cal s^(-1)cm^(-1) ""^@C^(-1) .
Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`Delta x = 10 <a href="https://interviewquestions.tuteehub.com/tag/mm-1098795" style="font-weight:bold;" target="_blank" title="Click to know more about MM">MM</a> = 1 cm` <br/> `K = 0.7 <a href="https://interviewquestions.tuteehub.com/tag/cal-412083" style="font-weight:bold;" target="_blank" title="Click to know more about CAL">CAL</a> s^(-1) cm^(-1) K^(-1)` <br/> ` <a href="https://interviewquestions.tuteehub.com/tag/q-609558" style="font-weight:bold;" target="_blank" title="Click to know more about Q">Q</a> = 5 xx 10^5 cal , A = 1m^2 = 10^4cm^2`<br/> t = 1 min = 60 s <br/> ` Q = (KA(T_1 - T_2)t)/(Delta x)` <br/> ` rArr T_1 - T_2 = (Q Delta x)/(KA t) = (5 xx 10^5 xx 1)/(0.7 xx 10^4 xx 60)` <br/> ` T_1 - T_2 = 1.19^@C`</body></html>