1.

What will be the electrode potential of that hydrogen electrode which is filled withh HCL solution of pH value 1.0

Answer»

`-59.15V`
`+59.15V`
`+59.15mV`
`-59.15mV`

Solution :`E_(H^(+)//H_(2))=E_(H^(+)//H_(2))^(0)-(0.05915)/(1)"LOG"(1)/([H^(+)])`
`=0+0.05915log[H^(+)]"VOLT"=-0.05915pH`
`=-0.05915xx1=-0.05915V=-59.15mV`.


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