What will be the γ value for starter taking 4 steps, where ratio of resistance at maximum allowable current to armature resistance is equal to 1.8?(a) 1.2164(b) 1.8(c) 2.2468(d) 0.8220I have been asked this question at a job interview.I need to ask this question from Starting of DC Motors topic in section DC Motors of DC Machines

What will be the γ value for starter taking 4 steps, where ratio of r

1.	What will be the γ value for starter taking 4 steps, where ratio of resistance at maximum allowable current to armature resistance is equal to 1.8?(a) 1.2164(b) 1.8(c) 2.2468(d) 0.8220I have been asked this question at a job interview.I need to ask this question from Starting of DC Motors topic in section DC Motors of DC Machines
Answer» The correct answer is (a) 1.2164 The best I can explain: γ is DEFINED as the ratio of upper current limit to the lower current limit in starters of DC machine. γ ^n-1 = ratio of RESISTANCE at MAXIMUM allowable current to the armature resistance. Substituting values for n=4, we GET γ=1.2164.

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