What will be the heat change at constant volume for the reaction whose heat change at constant pressure is -560 kcal at 27^(@)C? The reaction is C_(8)H_(16) + 12O_(2) to 8CO_(2) + 8H_(2)O (Given R = 2 cal mol^(-1)K^(-1))

What will be the heat change at constant volume for the reaction whose

1.	What will be the heat change at constant volume for the reaction whose heat change at constant pressure is -560 kcal at 27^(@)C? The reaction is C_(8)H_(16) + 12O_(2) to 8CO_(2) + 8H_(2)O (Given R = 2 cal mol^(-1)K^(-1))
Answer» `-557600` calories `442800` calories `-561800` calories `368240` calories Solution :`DeltaH = -560 kcal, DELTAU = ?` `C_(8)H_(16)(l) + 12O_(2)(g) to 8CO_(2)(g) + 8H_(2)O(l)` `DeltaH = DeltaU + Deltan_(g) RT` `Deltan_(g) = 8 -12 = -4` `-560000 = DeltaU + (-4) xx 2 xx 300` = `-557600`.