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What will be the ionisation constant of formic acid if its 0.01 M solution is `14.5%` ionised ?A. `2.1xx10^(-4)`B. `14.5`C. `0.145`D. `1.45xx10^(-4)` |
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Answer» Correct Answer - A `K_(a)=calpha^(2)` `=(14.5)/(100)=0.145` `K_(a)=0.01xx(0.145)^(2)=2.1xx10^(-4)` |
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