What will be the minimum pressure required to compress 500 dm^(3) of air at 1 bar to 200 dm^(3) at 30^(@)C ?

What will be the minimum pressure required to compress 500 dm^(3) of a

1.	What will be the minimum pressure required to compress 500 dm^(3) of air at 1 bar to 200 dm^(3) at 30^(@)C ?
Answer» Solution :At CONSTANT temperature, VOLUME of GAS for fixed volume pressure will be calculated by Boyle.s formula. At `30^(@)C` Boyle.s equaltion, `p_(1)V_(1)=p_(2)V_(2)` where, `p_(1)=` Initial pressure = 1 bar `V_(1)=` Initial volume `= 500 dm^(3)` `V_(2)=` Final volume `= 200 dm^(3)` `p_(2)=` Final pressure = (?) `therefore p_(2) =(p_(1)V_(1))/(V_(2))` `= (("1 bar")xx(500 dm^(3)))/(200 dm^(3))=2.5` bar Minimum pressure to be KEPT is 2.5 bar.