Saved Bookmarks
| 1. |
What will be the minimum pressure required to compress 500dm^(3) of air at 1 bar to 200 dm^(3) at 30^(@)C ? |
|
Answer» <P> Solution :`P_(1)=1` bar,`V_(1)=500 dm^(3)``P_(2)=?,V_(2)=200 dm^(3)` As TEMPERATURE remains constant at `30^(@)C`, applying Boyle's law, `P_(1)V_(1)=P_(2)V_(2)` `1 barxx500 dm^(3)=P_(2)xx200 dm^(3)"or"P_(2)=(500)/(200)bar=2.5 bar` |
|