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what will be the minimum pressure required to compress 500dm cube of air at 1bar to 200dm to 30 degree celcius |
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Answer» P₁ = 1P₂ = ? V₁= 500 dm³V₂= 200 dm³ Apply boyle's law p₁V₁=p₂V₂ to calculate p₂ as temperature remains constant. p₂ = p₁V₁/ V₂ = 1 bar× 500 dm³/ 200 dm³ = 2.5 bar 2.5 is the required answer Hit like if you find it useful! |
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