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What will be the minimum pressure required to compress 500 dm3 of air at 1 bar to 200 dm3 at 30 °C? |
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Answer» p1 = 1 bar p = ? V1 = 500 dm3 V2 = 200 dm3 Temperature remains constant. According to Boyle’s law, p1V1 = p2V2 Or p2 = \(\frac{p_2V_2}{V_2}\) p2 = \(\frac{1\ bar\times500\ dm^3}{200\ dm^3}\) = 2.5 bar |
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