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What will be the molality of solution prepared by dissolving 3.7 g propanoic acid 80 g benzene ?A. 0.77 mB. 0.625 mC. 0.045 mD. 46.25 m |
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Answer» Correct Answer - B moles of acid `=(3.7)/(74)=0.05` molality of solution `=(w)/(m)xx(1000)/(w_(("ing")))=(0.05)/(80)xx1000` =0.625 |
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