1.

What will be the molarity of a solution, which contains 5.85g of NaCl_((s))per 500 mL ?

Answer»

4 mol `L^(-1)`
20 mol `L^(-1)`
0.2 mol `L^(-1)`
2 mol `L^(-1)`

Solution :Molarity (M) is obtained by following equation,
Molarity `=("weight" xx 1000)/("molecular weight" xx "volume (mL)")`
`=(5.85xx1000)/(58.5xx500) = 0.2 "mol "L^(-1)`
Note : Molarity of solution depends UPON the temperature because volume of solution is CHANGE with temerature .


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