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What will be the molarity of a solution, which contains 5.85g of NaCl_((s))per 500 mL ? |
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Answer» 4 mol `L^(-1)` Molarity `=("weight" xx 1000)/("molecular weight" xx "volume (mL)")` `=(5.85xx1000)/(58.5xx500) = 0.2 "mol "L^(-1)` Note : Molarity of solution depends UPON the temperature because volume of solution is CHANGE with temerature . |
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