1.

What will be the molarity of a solution, which contains 5.85 g of NaCl(s) per 500 mL?

Answer»

`4molL^(-1)`
`20molL^(-1)`
`0.2molL^(-1)`
`2molL^(-1)`

SOLUTION :`"Molarity"=("Moles of the solute")/("VOLUME of solution in L")=(5.85//58.5)/(0.500L)="0.2 MOL L"^(-1)`.


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