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What will be the molarity of the solution containing 18.25 g of HCl gas in 500 g of water ? |
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Answer» 0.1 m Thus, Molality `=("Moles of solute")/("MASS of solvent (in kg)")` ......(i) GIVEN that, Mass of solvent `(H_(2)O)=500 g = 0.5 kg` Weight of HCl `= 18.25g` Molecular weight of HCl `= 36.5 g` Moles of HCl `= (18.25)/(35.6)=0.5` `m= (0.5)/(0.5)=1 m` ...( `:. (i)` ) |
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