1.

What will be the molarity of the solution in which 0.365 g of HCl gas is dissolved in 100 mL of solution ?

Answer»

2 M
0.2 M
1 M
0.1 M

SOLUTION :No. of moles in 0.365g of HCl `=(0.365)/(36.5)=0.01`
VOLUME of solution in L `=100/1000=0.1L`
MOLARITY `=n/(V("in L"))=(0.01)/(0.1)=0.1M`


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