1.

What will be the normality of a solution containing 4.9 g H_(3) PO_(4) dissolved in 500 ml water ?

Answer»

`0.3`
`1.0`
`3.0`
`0.1`

Solution :`N=(w xx 1000)/(E xx "VOLUME in ML."),E = (98)/(3) = 32.6`
`N=(4.9xx1000)/(32.6xx500)=0.3 N`.


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