1.

What will be the notmality of resulting solution obtained by mixing 4 mL 0.05 M H_(2)SO_(4(aq)) solution and 6 mL 0.3 M _(2)SO_(4(aq)) ?

Answer»

0.175 N
0.35 N
0.4 N
0.2 N

SOLUTION :`M=(N_(1)V_(1)+N_(2)V_(2))/((V_(1)+V_(2)))`
`= (0.05xx4+0.3xx6)/(4+6)=(0.2+1.8)/(10)=0.2`
Now, `N = M xx2=0.2xx2=0.4`


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