1.

What will be the osmotic pressure of the solution prepared by dissolving 1.75 gram sucrose in 50 mL. solution at 17^(@)C temperature ?

Answer»

`0.406`
`8.12`
`0.822`
`0.0406`

Solution :`T=17^(@)C=293K, w=1.75 G, V=0.15 L`
`PI = (WRT)/(MV)=(1.75xx0.08314xx293)/(342xx0.15)=0.822` bar.


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