1.

What will be the passenger carrying capacity of a balloon of diameter 20 m and mass 100 kg filled with helium at 1.0 atm at 27^(@)C. Density of air is 1.2 "kg"//m^(3) and average weight of a passenger is 65 kg.

Answer»

55
60
65
70

Solution :Volume of AIR displaced by balloon = volume of balloon
= `(4)/(3) pi r^(3)= (4)/(3) xx (22)/(7) xx 10^(3)=4190.47 m^(3) or 4190.47 xx 10^(3) L`
`"Mass of air displaced by balloon" = 4190.47 xx 1.2 = 5028.56 g`.
Number of moles of He in balloon, `n = (PV)/(RT) = (1 xx4190.47 xx 10^(3))/( 0.082 xx 300)= 170344`
`"Mass of filled balloon" = 681.376 + 100 = 781.376 g`. 
`"Pay load of balloon" = "mass of air displaced" – "mass of filled balloon" = 5028.56 - 781.376 = 4247.184 g`
`"Passenger carrying capacity" = ("Payload")/("Average wt.of Passenger")= 4247.184 65 = 65.3 = 65 "Passengers"`.


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