1.

What will be the pH of a solution formed by mixing 40 ml of 0.10 M HCl with 10 ml of 0.45 M NaOH

Answer»

12
10
8
6

Solution :M.eq. of 0.01 M HCL `= (0.10)/(1000) xx 40 = 0.004 M`
M.eq. of 0.45 M NAOH `= (0.45 xx 10)/(1000) = 0.0045 M`
Now left `[OH^(-)] = 0.0045 - 0.004 = 5 xx 10^(-4)M`
Total volume = 50 ml
`[OH^(-)] = (5 xx 10^(-4))/(50) xx 1000, [OH^(-)] = 1 xx 10^(-2)`
`pOH = 2, pH = 14 - pOH = 12`.


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