1.

What will be the pH of the resulting solution if to a 100 ml of HCl solution of pH = 1.0, 900 ml of distilled water is added ?

Answer»


SOLUTION :100 ml has been DILUTED to 1000 ml . Hence, dilution, = 10times.
Now, `[H^(+)] = 10^(-1)//10 = 10^(-2)M :.pH = 2`


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