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What will be the pressure of the gas mixture when 0.5 L of H_(2) at 0.8 bar 2.0 L of oxygen at 0.7 bar are introduced in a 1L vessel at 27^(@)C ?

Answer»

Solution :Calculation of partial pressure of `H_(2)` in 1L VESSEL
`P_(1)=0.8 bar,"" V_(1)=0.5 L`
`P_(2)=? "" V_(2)=1.0 L`
As temperature remains constant, `P_(1)V_(1)=P_(2)V_(2)`
`(0.8" bar")(0.5 L)=P_(2)(1.0 L)"or"P_(2)=0.40" bar", i.e., p_(H_(2))=0.40"bar"`
Calculation of partial pressure of `O_(2)` in 1L vessel
`P'_(1)V'_(1)=P'_(2)V'_(2)`
`(0.7" bar")(2.0 "bar")=P'_(2)(1 L) or P'_(2)=1.4" bar", i.e., P_(O_(2))=1.4 "bar"`
`:."" "TOTAL pressure"=P_(H_(2))+P_(O_(2))=1.4 "bar"+1.4" bar"=1.8" bar"`


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