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What will be the ratio of de - Broglie wavelengths of proton and `alpha` - particle of same energy ?A. 1B. 2C. 4D. `0.25` |
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Answer» Correct Answer - B de-Broglie wave length `lamda = (lamda)/(P)=(lamda)/(sqrt(2km)) rArr (lamda_(P))/(lamda_(alpha)) = sqrt((m_(alpha))/(m_(rho)))=2` |
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