What will be the recurrence relation of the code of recursive insertion sort?(a) T(n) = 2T(n/2) + n(b) T(n) = 2T(n/2) + c(c) T(n) = T(n-1) + n(d) T(n) = T(n-1) + cThe question was asked in an interview for job.The origin of the question is Sorting in section Sorting of Data Structures & Algorithms II

What will be the recurrence relation of the code of recursive insertio

1.	What will be the recurrence relation of the code of recursive insertion sort?(a) T(n) = 2T(n/2) + n(b) T(n) = 2T(n/2) + c(c) T(n) = T(n-1) + n(d) T(n) = T(n-1) + cThe question was asked in an interview for job.The origin of the question is Sorting in section Sorting of Data Structures & Algorithms II
Answer» RIGHT ANSWER is (c) T(n) = T(n-1) + n Easy explanation - The recurrence relation of the CODE of recursive insertion sort is T(n) = T(n-1) + n. It can be solved by the method of substitution and is found to be EQUAL to n^2.

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