What will be the strength of 20 vol of H_(2)O_(2) in terms of gram per

1.	What will be the strength of 20 vol of H_(2)O_(2) in terms of gram per litre?
Answer» `60.71 GL^(-1)` `5.6 gL^(-1)` `30.62 gL^(-1)` `17 gL^(-1)` Solution :20 vol of `H_(2)O_(2)` means : 1 L of this `H_(2)O_(2)` will give 20 L of oxygen at sTP. `underset(2xx34)(2H_(2)O_(2))to underset(22.4" L at STP")(O_(2))+H_(2)O` 22.4 L of `O_(2)` is PRODUCED from 68 g of `H_(2)O_(2)` 20 L of `O_(2)` is produced from `=(68xx20)/(22.4)=60.71 g L^(-1)`of `H_(2)O_(2)`.

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