1.

What will be the strength of 20 vol of `H_(2)O_(2)` in terms of gram per litre?A. `60.71 gL^(-1)`B. `5.6 gL^(-1)`C. `30.62 gL^(-1)`D. `17 gL^(-1)`

Answer» Correct Answer - A
20 vol of `H_(2)O_(2)` means :
1 L of this `H_(2)O_(2)` will give 20 L of oxygen at sTP.
`underset(2xx34)(2H_(2)O_(2))to underset(22.4" L at STP")(O_(2))+H_(2)O`
22.4 L of `O_(2)` is produced from 68 g of `H_(2)O_(2)`
20 L of `O_(2)` is produced from `=(68xx20)/(22.4)=60.71 g L^(-1)` of `H_(2)O_(2)`.


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