1.

What will be the temperature when the rms velocity is four times of that at 300 K ?

Answer»

300 K
900 K
4800 K
1200 K

Solution :(C ) `U_(rms)("velocity")=sqrt((3RT)/(M))`
HENCE, `upropsqrttrArr(u_(1))/(u_(2))=sqrt((T_(1))/(T_(2)))` From Eq. (i), `(1)/(4)=sqrt((300)/(T_(2)))`
`(1)/(16)=(300)/(T_(2))`
`T^(2)=16xx300`
4800 K


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