1.

What will be the temperature when the rms velocity is four times of that at 300 K ?A. 300 KB. 900 KC. 4800 KD. 1200 K

Answer» (c ) `U_(rms)("velocity")=sqrt((3RT)/(M))`
Hence, `upropsqrttrArr(u_(1))/(u_(2))=sqrt((T_(1))/(T_(2)))` From Eq. (i), `(1)/(4)=sqrt((300)/(T_(2)))`
`(1)/(16)=(300)/(T_(2))`
`T^(2)=16xx300`
4800 K


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