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What will be the value of current I in the circuit shown ? A. 0.67 AB. 1AC. 0.32 AD. None of these

Answer» Correct Answer - A
Applying `KVL, V_(A)-V_(D)=-6i-5i+10-4i`
Here, `V_(A)-V_(D)=0`
Since, points A and D are centred.
`-6i+5i+10-4i=0 rArr 15i=10`
`rArr " " i=(10)/(15)=0.67 A`


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