1.

What will be the value of K and Delta G^(@) for the process of transformation of ice into water at room temperature ?

Answer»

`K=1, Delta G^(@)` Zero
`K lt 1, Delta G^(@)` positive
`K GT 1, Delta G^(@)` positive
`K gt 1, Delta G^(@)` negative

Solution :ICE cube will spontaneously convert into water at room TEMPERATURE and `"ice"_((s)) to` Liquid water reaction will be spontaneous FORWARD reaction.
`therefore` According to second law of thermodynamics value of `Delta G^(@)` will be negative. Moreover the amount of product is HIGHER by forward reaction. So `K= ("[product]")/( "[reactant]") gt 1`


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