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What will be the value of molality for an aqueous solution of 10% w/W NaOH?A. `2.778`B. 5C. 10D. `2.5`

Answer» Correct Answer - A
Let mass of solution = 100 g `therefore` Mass of NaOH = 10 g
Mass of solvent = 90 g
`therefore` Molality `=((10)/(40))/((90)/(1000))=(10)/(40)xx(1000)/(90)=2.778`.


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