What will be the value of [OH^(-)]^(2) in the 0.1 M solution of ammonium hydroxide having K_(b)=1.8xx10^(-5)?

What will be the value of [OH^(-)]^(2) in the 0.1 M solution of ammoni

1.	What will be the value of [OH^(-)]^(2) in the 0.1 M solution of ammonium hydroxide having K_(b)=1.8xx10^(-5)?
Answer» `1.8xx10^(-7)` `1.8xx10^(-6)` `1.8xx10^(-4)` `1.8xx10^(-3)` Solution :`{:(,NH_(4)OH,hArr,NH_(4)^(+),+,OH^(-),,),("Initial conc. :",0.1 M ,,0,,0,,),("At EQM. :",0.1 (1-ALPHA),,0.1 alpha,,0.1 alpha,,),(,,,,,,,):}` `K_(b) =([NH_(4)^(+)][OH^(-)])/([NH_(4)OH])=([OH^(-)]^(2))/([NH_(4)OH])` `[:' [NH_(4)^(+)]=[OH^(-)]]` `:. [OH^(-)]^(2) = K_(b) xx [ NH_(4)OH]` `=1.8xx10^(-5)xx0.1=1.8xx10^(-6)`