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What will be the value of pH of 0.01 mol dm^(-3) CH_3COOH (K_a=1.74xx10^(-5) ) ? |
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Answer» Solution :If `K_a=1.74xx10^(-5)` Concentration of `CH_3COOH`= 0.01 MOL `dm^(-3)` `[H^+]=sqrt(K_a. C)` `=sqrt(1.74xx10^(-5)xx0.01)=4.17xx10^(-4)` `pH=-LOG[H^+]` `=-log(4.17xx10^(-4))`=3.4 |
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