What will be the value of pH of 0.01 mol dm^(-3) cH_(3)CO OH (K_(a) = 1.74 xx 10^(-5))?

What will be the value of pH of 0.01 mol dm^(-3) cH_(3)CO OH (K_(a) =

1.	What will be the value of pH of 0.01 mol dm^(-3) cH_(3)CO OH (K_(a) = 1.74 xx 10^(-5))?
Answer» 3.4 3.6 3.9 `3.0` Solution :`pH = (1)/(2) (pK_(a)-LOG C)=(1)/(2) [-log (1.74xx10^(-5))-log 10^(-2)]` `=(1)/(2) [ (5-0.2405) + 2] = (1)/(2) (6.76) = 3.38 ~= 3.4`.