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What will be the vapour pressure of the solution of 18 gram glucose dissolve in 178.2 gram water at 100^(@)C temp. ? |
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Answer» 706.4 mm Mole of GLUCOSE `(n)=(18)/(180)=0.1` `THEREFORE (p^(@)-p)/(p^(@))=(n)/(n+N) therefore p=752.4` mm |
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