1.

What will be the vapour pressure of the solution of 18 gram glucose dissolve in 178.2 gram water at 100^(@)C temp. ?

Answer»

706.4 mm
752.4 mm
750 mm
760 mm

Solution :Mole of water `(N)=(178.2)/(18)=9.9`
Mole of GLUCOSE `(n)=(18)/(180)=0.1`
`THEREFORE (p^(@)-p)/(p^(@))=(n)/(n+N) therefore p=752.4` mm


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